Question

В треугольнике ABC AC=BC . Угол C равен 70 градусов . Найдите внешний угол CBD . Ответ дайте в градусах

Answer 1

Треугольник равнобедренный, углы при основании равны: (180-70)/2=55°. Значит внешний угол CBD будет равен:
180°-55°=125°

Answer 2

Triangle ABC

In triangle ABC, we are given that AC = BC and angle C is equal to 70 degrees. We need to find the external angle CBD in degrees.

Solution

To find the external angle CBD, we can use the fact that the sum of the measures of the angles of a triangle is always 180 degrees.

Since AC = BC, triangle ABC is an isosceles triangle. In an isosceles triangle, the base angles (the angles opposite the equal sides) are equal. Therefore, angle A = angle B.

Let's denote the external angle CBD as x. Since angle C is 70 degrees, angle A and angle B are both (180 - 70)/2 = 55 degrees.

Now, we can find the external angle CBD by subtracting the sum of angles A and B from 180 degrees:

x = 180 - (angle A + angle B) x = 180 - (55 + 55) x = 180 - 110 x = 70 degrees

Answer

The measure of the external angle CBD is 70 degrees.