Question

как изменится площадь прямоугольного треугольника,если один из катетов уменьшить в 8 раз?

Answer 1

S=a*b

S=8a*b/3

увеличится в 2 2/3 раза

(в 2 целых две третьих раза)

Answer 2

Changes in the Area of a Right Triangle when One Leg is Reduced by 8 Times

To determine how the area of a right triangle changes when one of its legs is reduced by 8 times, we need to understand the relationship between the legs and the area of a right triangle.

The area of a right triangle is given by the formula: Area = (1/2) * base * height, where the base and height are the two legs of the triangle.

Let's assume the original legs of the right triangle are a and b, with a being the leg that will be reduced by 8 times. After reducing a by 8 times, the new length of a will be a/8.

To find the new area of the right triangle, we substitute the new values into the area formula:

New Area = (1/2) * (a/8) * b

Simplifying the expression, we get:

New Area = (1/16) * a * b

Therefore, when one of the legs of a right triangle is reduced by 8 times, the new area of the triangle is (1/16) times the original area.

Please note that the above explanation assumes that the other leg, b, remains unchanged. If both legs are reduced by 8 times, the new area will be (1/64) times the original area.

I hope this helps! Let me know if you have any further questions.