Question

Точки А(2,-4,-8) і B(10,-20,6) симетричні відносно точки С. Знайдіть координати точки С

Answer 1

Т.к. точки А и В симметричны относительно точки С, то С-середина АВ, значит
x(C)=(x(B)+x(A))/2=(2+10)/2=6
y(C)=(y(B)+y(A))/2=(-4-20)/2=-12
z(C)=(z(B)+z(A))/2=(-8+6)/2=-1

С(6;-12;-1)

Answer 2

Х=2+10=12/2=6
у=-4-20=-24/2=-12
z=-8+6=-2/2=-1
C(6,-12,-1)

Answer 3

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The user's message is a mathematical problem that asks to find the coordinates of point C, which is the midpoint of points A(2,-4,-8) and B(10,-20,6). To answer this question in detail, I will use the formula for finding the midpoint of a line segment:

$$C = \left(\frac{x_A + x_B}{2}, \frac{y_A + y_B}{2}, \frac{z_A + z_B}{2}\right)$$

Substituting the values of A and B, we get:

$$C = \left(\frac{2 + 10}{2}, \frac{-4 - 20}{2}, \frac{-8 + 6}{2}\right)$$

Simplifying, we get:

$$C = (6, -12, -1)$$

Therefore, the coordinates of point C are (6, -12, -1).

I hope this answer was helpful. If you have any other questions or requests, please let me know.Ответь+подробно.+Точки+А(2,-4,-8)+і+B(10,-20,6)+симетричні+відносно+точки+С.+Знайдіть+координати+точки+С