Question

Какой длины может быть сторона АВ треугольника АВС , если АВ на 2 см больше АС/2 и на 32 см меньше 2ВС?

Answer 1

Скорее всего ответ = -8, попробуй взять сторону АВ за Х и вырази

Answer 2

I can answer your question in detail. The length of the side AB of the triangle ABC can be found by using the following steps:

- Let AB = x, AC = y, and BC = z. Then, from the given conditions, we have: - x = y/2 + 2 - x = 2z - 32 - Solving these equations for x, we get: - x = (y + 4)/2 - x = (y + 4)/2 = 2z - 32 - y + 4 = 4z - 64 - y = 4z - 68 - Now, we can use the triangle inequality theorem, which states that the sum of any two sides of a triangle must be greater than the third side, to find the possible values of x. That is, we have: - x + y > z - x + z > y - y + z > x - Substituting the expressions for x and y in terms of z, we get: - (4z - 64)/2 + (4z - 68) > z - (4z - 64)/2 + z > (4z - 68) - (4z - 68) > (4z - 64)/2 - Simplifying these inequalities, we get: - z > 34 - z < 68 - z > 17 - Combining these inequalities, we get the range of possible values for z: - 34 < z < 68 - Finally, we can plug in the values of z in this range into the expression for x to get the possible values of x. For example, if z = 35, then x = 2z - 32 = 2(35) - 32 = 38. Similarly, if z = 67, then x = 2z - 32 = 2(67) - 32 = 102. Therefore, the possible values of x are between 38 and 102. That is, the length of the side AB of the triangle ABC can be any number from 38 cm to 102 cm.

I hope this answer helps you understand the problem. If you want to learn more about triangles and their properties, you can check out some of the web search results I found for you . Have a nice day!