Question

Найти площадь равнобедренной трапеции ABCD, если высота BH = 9см, основание ВС =9см, а отрезок AH = 3 см. УМОЛЯЮ ,помогите срочно. ПОЖАЛУЙСТА ПРОШУ , СРОЧНО НАДО

Answer 1

Площадь трапеции ((ВС + АД ):2 )хВН это в нашем случае. Трапеция равнобедренная , значит, вд= ан= 3 см, значит АД= 3+3+9=15 см, итого (9+15):2х9=108

Answer 2

S=9+3\2=6*9=54 ответ::площадь равна 54см

Answer 3

Finding the Area of a Isosceles Trapezoid

To find the area of an isosceles trapezoid, we can use the formula:

Area = (1/2) * (sum of the bases) * height

In this case, we are given the following measurements: - Height (BH) = 9 cm - Base BC = 9 cm - Segment AH = 3 cm

To find the area, we need to determine the lengths of the other two bases, AB and CD.

Let's start by finding the length of base AB. Since the trapezoid is isosceles, we know that base AB is equal to base CD. Therefore, we only need to find the length of one of the bases.

To find the length of base AB, we can use the following equation:

AB = BC - AH

Substituting the given values, we have:

AB = 9 cm - 3 cm = 6 cm

Now that we have the lengths of both bases, we can calculate the area using the formula mentioned earlier:

Area = (1/2) * (AB + CD) * BH

Substituting the values we have:

Area = (1/2) * (6 cm + 9 cm) * 9 cm

Calculating the expression inside the parentheses:

Area = (1/2) * 15 cm * 9 cm

Multiplying the values:

Area = 7.5 cm * 9 cm

Calculating the final result:

Area = 67.5 cm²

Therefore, the area of the isosceles trapezoid ABCD is 67.5 cm².

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