Question

Смежные стороны пар-мма равны 12 см и 14 см , а его острый угол равен 30 градусам. Найти нужно площадь пар-мма.

Answer 1

S=а*в*sinА
S=12*14*sin30=168*0,5=84см^2

Answer 2

Given Information:

We are given that the adjacent sides of a parallelogram are 12 cm and 14 cm, and one of its acute angles is 30 degrees. We need to find the area of the parallelogram.

Solution:

To find the area of a parallelogram, we can use the formula: Area = base × height.

In a parallelogram, the base is the length of one of its adjacent sides, and the height is the perpendicular distance between the base and the opposite side.

To find the height, we can use trigonometry. Since we know one of the acute angles is 30 degrees, we can use the sine function to find the height.

Let's label the parallelogram as ABCD, where AB and BC are the adjacent sides.

From the given information, we have: AB = 12 cm BC = 14 cm Angle B = 30 degrees

To find the height, we need to find the length of the perpendicular from point B to side AD.

Using trigonometry, we can write: sin(30 degrees) = height / AB

Rearranging the equation, we get: height = AB × sin(30 degrees)

Substituting the values, we have: height = 12 cm × sin(30 degrees)

Now, we can calculate the height using a calculator or by referring to trigonometric tables.

Let's calculate the height: height = 12 cm × 0.5 height = 6 cm

Now that we have the base and height, we can calculate the area of the parallelogram: Area = base × height Area = 14 cm × 6 cm Area = 84 cm²

Therefore, the area of the parallelogram is 84 cm².

Answer:

The area of the parallelogram with adjacent sides of 12 cm and 14 cm, and an acute angle of 30 degrees is 84 cm².