Question

Луч OK является биссектрисой угла AOB.Найди величину угла KOB, если угол AOB = 70°.

Answer 1

Т.к биссектриса делит угол на две равные части: <AOK и <KOB, которые будут равны половине угла AOB = 70°.

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Ответ:<KOB=<AOK=35°!!!!!!!!!!!!!!!!

Answer 2

Так как ОК является бессектрисой угла АОВ, то он делит его попалам. Значит угол КОВ равен 70\2=35

Answer 3

Given Information:

We are given that angle AOB is 70° and OK is the bisector of angle AOB.

Solution:

To find the measure of angle KOB, we can use the fact that OK is the bisector of angle AOB.

Since OK is the bisector of angle AOB, it divides the angle into two equal parts. Therefore, angle KOB is equal to half of angle AOB.

Using the given information that angle AOB is 70°, we can calculate the measure of angle KOB as follows:

Angle KOB = (Angle AOB) / 2

Substituting the value of angle AOB as 70°:

Angle KOB = 70° / 2 = 35°

Therefore, the measure of angle KOB is 35°.

Answer:

The measure of angle KOB is 35°.