Question

Основа прямого паралелепіпеда-ромб з діагоналями 6см і 8см.Бічне ребро паралелепіпеда дорівнює 5 см.Зайти обєм паралелепіпеда

Answer 1

V=a*b*h
для того чтобы узнать чeму равно а и b их следует найти по теоремепифагора.
а=5,b=5.
V=5*5*5=125

Answer 2

Calculating the Volume of a Parallelepiped with a Rhombus Base and Diagonals of 6cm and 8cm

To calculate the volume of a parallelepiped with a rhombus base and diagonals of 6cm and 8cm, we can use the formula for the volume of a parallelepiped, which is given by:

Volume = Base Area * Height

The base area of the parallelepiped with a rhombus base can be calculated using the formula for the area of a rhombus, which is:

Base Area = (d1 * d2) / 2

Where d1 and d2 are the diagonals of the rhombus.

Given: - Diagonal 1 (d1) = 6cm - Diagonal 2 (d2) = 8cm - The lateral edge of the parallelepiped = 5cm

Calculations

1. Calculating the Base Area: - Using the formula for the area of a rhombus, we can calculate the base area: ``` Base Area = (6 * 8) / 2 = 24 square cm ```

2. Calculating the Volume: - Now, we can calculate the volume of the parallelepiped using the base area and the given lateral edge: ``` Volume = Base Area * Height = 24 * 5 = 120 cubic cm ```

Conclusion

The volume of the parallelepiped is 120 cubic cm.