
Рівняння прямої, що проходить через точки Z (-7; -1) i N (2; 4


Ответы на вопрос

Объяснение:
y=kx+b
-1 = -7k + b
4 = 2k + b
-9k = -5
k = 5/9
-1 = -7 * 5/9 + b
b = 2 8/9
y = 5/9x + 2 8/9



Equation of a Line Passing Through Two Points
To find the equation of a line passing through points Z(-7, -1) and N(2, 4), we can use the point-slope form of a linear equation, which is given by:
y - y1 = m(x - x1)
Where: - (x1, y1) are the coordinates of one of the points on the line. - m is the slope of the line.
Calculating the Slope (m)
The slope of a line passing through two points (x1, y1) and (x2, y2) is given by:
m = (y2 - y1) / (x2 - x1)
Using the coordinates of points Z(-7, -1) and N(2, 4): - x1 = -7, y1 = -1 - x2 = 2, y2 = 4
We can calculate the slope (m) using the formula: m = (4 - (-1)) / (2 - (-7))
m = (4 + 1) / (2 + 7) m = 5 / 9
So, the slope (m) is 5/9.
Using Point-Slope Form to Find the Equation
Now that we have the slope (m) and a point (x1, y1), we can use the point-slope form to find the equation of the line.
Using point Z(-7, -1): y - (-1) = (5/9)(x - (-7)) y + 1 = (5/9)(x + 7)
This is the equation of the line passing through points Z(-7, -1) and N(2, 4).
Final Equation
The final equation of the line passing through points Z(-7, -1) and N(2, 4) is: y + 1 = (5/9)(x + 7)

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