Question

Биссектриса острого угла параллеграмма делит его сторону в отношении 2:3 ,считая от вершины тупого угла . периметр параллеграмма равен 42 .найдите стороны решите пж ​

Answer 1

Ответ:

Биссектриса отсекает от параллелограмма равнобедренный треугольник (тема: углы при параллел-ных прямых и секущей)

Если меньшая сторона 3х, большая 7 х, то весь периметр 20х

20х=80

х =4

Одна сторона 12, другая 28

Answer 2

Bisector of an acute angle of a parallelogram

To find the sides of the parallelogram, we need to use the information given about the bisector of an acute angle. Let's break down the problem step by step.

1. Let's assume that the length of the shorter side of the parallelogram is 2x and the length of the longer side is 3x. This is based on the given information that the bisector divides the side in a ratio of 2:3.

2. According to the properties of a parallelogram, opposite sides are equal in length. So, the other pair of sides will also have lengths of 2x and 3x.

3. The perimeter of a parallelogram is the sum of all its sides. In this case, the perimeter is given as 42. So, we can set up the equation:

2x + 3x + 2x + 3x = 42

Simplifying the equation, we get:

10x = 42

Solving for x, we find:

x = 4.2

4. Now that we have the value of x, we can find the lengths of the sides:

- Length of the shorter side = 2x = 2 * 4.2 = 8.4 - Length of the longer side = 3x = 3 * 4.2 = 12.6

Therefore, the sides of the parallelogram are approximately 8.4 and 12.6.

Please note that these calculations are based on the assumption that the bisector divides the side in a ratio of 2:3. If there is any additional information or clarification needed, please let me know.