Question

В параллелограмме ABCD луч AM-биссектриса угла BAD.Найдите углы параллелограмма ABCD,если угол BMA=25 градусов.Срочно 10-15 минут.Зарание спасибо.

Answer 1

50, 130,50,130
там получаются накрест лежащие углы

Answer 2

Given Information:

In parallelogram ABCD, ray AM is the angle bisector of angle BAD. The angle BMA is given as 25 degrees.

Solution:

To find the angles of parallelogram ABCD, we can use the properties of a parallelogram and the given information.

Since ABCD is a parallelogram, opposite angles are congruent. Therefore, angle BCD is also 25 degrees.

Since AM is the angle bisector of angle BAD, angles BAM and DAM are congruent. Let's denote the measure of angle BAM as x degrees. Then, angle DAM is also x degrees.

Since ABCD is a parallelogram, opposite angles are congruent. Therefore, angle CDA is also x degrees.

Since the sum of the angles in a triangle is 180 degrees, we can write the following equation: x + x + 25 = 180

Simplifying the equation: 2x + 25 = 180 2x = 180 - 25 2x = 155 x = 155/2 x = 77.5

Therefore, angle BAM = angle DAM = 77.5 degrees.

To find the measure of angle BCD, we can use the fact that the sum of the angles in a quadrilateral is 360 degrees. Since ABCD is a parallelogram, opposite angles are congruent. Therefore, angle BCD is also 77.5 degrees.

To summarize: - Angle BMA = 25 degrees - Angle BAM = Angle DAM = 77.5 degrees - Angle BCD = 77.5 degrees

Note: The angles of a parallelogram can vary depending on the specific dimensions and properties of the parallelogram. The given information allows us to determine the measures of the angles in this particular parallelogram.

I hope this helps! Let me know if you have any further questions.