Question

Д)(х-3)²+у²=36 ж)х²+у²=1 е)х²+(у+2)²=4 з)х²+у²=5

Answer 1

д) график - окружность, смещен на 3 ед вправо, r =6. (см картинку 1)

ж) график - окружность, r =1 (картинка 2)

е) график - окружность, смещен на 2 ед вниз , r=2 ( картинка 3)

з) график - окружность, r=корень из 5 ( примерно 2, 3)

Answer 2

It looks like you have provided a set of equations with variables x and y. Each equation represents a different geometric shape. Let's analyze each equation and see what shape they represent:

а) (х-3)² + у² = 36

This equation represents a circle with its center at (3, 0) and a radius of 6 units. The general equation of a circle is (x - h)² + (y - k)² = r², where (h, k) represents the center of the circle and r is the radius.

ж) х² + у² = 1

This equation represents a circle with its center at the origin (0, 0) and a radius of 1 unit. Since the equation has no terms involving x or y separately, it represents a circle centered at the origin.

е) х² + (у + 2)² = 4

This equation represents a circle with its center at (0, -2) and a radius of 2 units. The general equation of a circle is (x - h)² + (y - k)² = r², where (h, k) represents the center of the circle and r is the radius.

з) х² + у² = 5

This equation represents a circle with its center at the origin (0, 0) and a radius of √5 (approximately 2.236) units.

So, in summary, we have:

• Equation а) represents a circle with center (3, 0) and radius 6.
• Equation ж) represents a circle with center (0, 0) and radius 1.
• Equation е) represents a circle with center (0, -2) and radius 2.
• Equation з) represents a circle with center (0, 0) and radius √5 (approximately 2.236).