Question

|b|=21, |a+b|=28, |a-b|=26|a| = ?​

Answer 1

Ответ: Асса

Объяснение:

Answer 2

We have the following information:

1. |b| = 21
2. |a + b| = 28
3. |a - b| = 26

We want to find the value of |a|.

Let's start by solving for the values of a + b and a - b using the given information:

1. |a + b| = 28 This implies that a + b could be either 28 or -28, as the absolute value of both of these values is 28.

2. |a - b| = 26 This implies that a - b could be either 26 or -26, as the absolute value of both of these values is 26.

Now, let's consider the two possibilities for each of the equations above and try to solve for a in each case:

Case 1: a + b = 28 and a - b = 26

Adding these two equations gives: (a + b) + (a - b) = 28 + 26 2a = 54 a = 27

Case 2: a + b = -28 and a - b = -26

Adding these two equations gives: (a + b) + (a - b) = -28 - 26 2a = -54 a = -27

So, we have two possible solutions for the value of a: a = 27 or a = -27.

Now, let's find the absolute value of a in each case:

1. |a| = |27| = 27
2. |a| = |-27| = 27

In both cases, the absolute value of a is 27.

So, |a| = 27.