Question

Tg^2 a-sin^2 a tg^2 a

Answer 1

Ответ:

Объяснение:

tg²α-sin²α*tg²α=tg²α*(1-sin²α)=tg²α*cos²α=cos²α*sin²α/cos²α=sin²α.

Answer 2

It appears you have an expression involving trigonometric functions and variables. If you want to simplify this expression, let's work through it step by step:

Expression: Tg^2(a) - sin^2(a) * tg^2(a)

First, let's notice that "Tg" likely represents the tangent function, and "sin" represents the sine function. To simplify this expression, we can use some trigonometric identities.

1. Start with the given expression: Tg^2(a) - sin^2(a) * tg^2(a)

2. Factor out the common factor of tg^2(a): tg^2(a) * (1 - sin^2(a))

3. Now, we can use the Pythagorean identity for sine: sin^2(a) + cos^2(a) = 1 So, 1 - sin^2(a) = cos^2(a)

4. Substitute cos^2(a) back into the expression: tg^2(a) * cos^2(a)

5. You can also use the identity for the tangent squared: tg^2(a) = sec^2(a) So, tg^2(a) * cos^2(a) = sec^2(a) * cos^2(a)

Depending on the level of simplification required, you can leave the expression as sec^2(a) * cos^2(a), or if you want to simplify further, you can use other trigonometric identities to reduce it.