Question

Периметр ромба равен 68 а площадь равна 204 найди высоту ромба

Answer 1

Ответ:

h=12ед

Объяснение:

Р=4а, где а-сторона ромба;

а=Р/4=68/4=17ед

S=a*h. →

h=S/a=204/17=12ед

Answer 2

Finding the Height of a Rhombus

To find the height of a rhombus, we need to know the perimeter and the area of the rhombus. In this case, the perimeter of the rhombus is given as 68 and the area is given as 204.

Let's denote the height of the rhombus as h.

To find the height, we can use the formula for the area of a rhombus:

Area = (diagonal1 * diagonal2) / 2

Since the diagonals of a rhombus are perpendicular bisectors of each other, we can express the diagonals in terms of the height:

diagonal1 = 2 * h diagonal2 = 2 * h

Substituting these values into the area formula, we get:

204 = (2 * h * 2 * h) / 2

Simplifying the equation, we have:

204 = 2 * h^2

Dividing both sides of the equation by 2, we get:

102 = h^2

Taking the square root of both sides, we find:

h = √102

Calculating the square root of 102, we get:

h ≈ 10.099

Therefore, the height of the rhombus is approximately 10.099.

Please note that the above calculations are based on the given information and assumptions about the rhombus. If there are any additional details or constraints, please let me know, and I'll be happy to assist you further.