Question

Сторона АС треугольника ABC равна 14, а высота, проведенная к ней, равна 17. Найди площадь треугольника ABC. В GUM за 17 А с 14 Н Ответ: кв. ед. С объяснениями дайте решение, а не просто ответ ​

Answer 1

Ответ:

S=1/2ac*h

S=1/2*14*17= 119^2

Ответ: 119 кв. ед.

Answer 2

Finding the Area of Triangle ABC

To find the area of triangle ABC, we can use the formula:

Area = (base * height) / 2

In this case, the base of triangle ABC is given as 14, and the height drawn to this base is given as 17. Plugging these values into the formula, we can calculate the area.

Area = (14 * 17) / 2

Simplifying the expression:

Area = 238 / 2

Area = 119 square units

Therefore, the area of triangle ABC is 119 square units.

I hope this helps! Let me know if you have any further questions.