Question

НВ прямоугольном треугольнике высота равна 15см , а отрезок гипотенузы АN-25см Найдите катет СВ​

Answer 1

BC^2 = BH^2 + CH^2 = 81 + 225 = 306;

BC = 3 * √32 см.

Прямоугольные треугольники буду подобные по 1 признаку

ВС / ВН = АС / СН;

АС = ВС * СН / ВН = 3 * √32 * 15 / 9 = 5 * √32 см.

Answer 2

Finding the length of the second leg of a right triangle

To find the length of the second leg of a right triangle, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

In this case, we are given that the height of the triangle is 15 cm and the length of the hypotenuse segment AN is 25 cm. We need to find the length of the second leg, SV.

Let's denote the length of SV as x. According to the Pythagorean theorem, we have the following equation:

x^2 + 15^2 = 25^2

Simplifying the equation, we get:

x^2 + 225 = 625

Subtracting 225 from both sides, we have:

x^2 = 400

Taking the square root of both sides, we find:

x = 20

Therefore, the length of the second leg SV is 20 cm.