Question

В треугольнике АВС АС = ВС= 12, СН - высота, sinA = 0,2. Найдите АВ.

Answer 1

Ответ:

48'6/5

Объяснение:

фото.

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Answer 2

Finding the Length of AB in Triangle ABC

To find the length of AB in triangle ABC, we can use the given information about the triangle and the sine of angle A.

Given: - AC = BC = 12 (equilateral triangle) - CH is the height of the triangle - sin(A) = 0.2

Solution

First, let's find the length of CH using the sine of angle A and the given information.

We know that sin(A) = opposite/hypotenuse, so we can use this to find CH: sin(A) = CH/AC CH = sin(A) * AC CH = 0.2 * 12 CH = 2.4

Now, we can find the length of AB using the Pythagorean theorem, as CH is the height of the equilateral triangle and AB is the base: AB^2 = AC^2 - CH^2 AB^2 = 12^2 - 2.4^2 AB^2 = 144 - 5.76 AB^2 = 138.24 AB = √138.24 AB ≈ 11.75

So, the length of AB in triangle ABC is approximately 11.75.