Question

допишіть до схеми реакцій та розставте коефіціенти: Ba+---- =>BaO;H20=> -----+O2;-----+O2=>P2O3

Answer 1

Reaction Scheme:

The given reaction scheme consists of three reactions:

1. Ba → BaO 2. H2O → O2 3. O2 → P2O3

Reaction 1: Ba → BaO

In this reaction, Barium (Ba) reacts to form Barium Oxide (BaO).

The balanced chemical equation for this reaction is:

Ba → BaO

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

The balanced equation with coefficients is:

2Ba → 2BaO

Reaction 2: H2O → O2

In this reaction, Water (H2O) decomposes to form Oxygen gas (O2).

The balanced chemical equation for this reaction is:

H2O → O2

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

The balanced equation with coefficients is:

2H2O → O2

Reaction 3: O2 → P2O3

In this reaction, Oxygen gas (O2) reacts to form Phosphorus Trioxide (P2O3).

The balanced chemical equation for this reaction is:

O2 → P2O3

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

The balanced equation with coefficients is:

4O2 → 2P2O3

Final Reaction Scheme:

Based on the given reactions and the balanced equations, the complete reaction scheme with coefficients is:

2Ba → 2BaO

2H2O → O2

4O2 → 2P2O3

Please note that the coefficients in the balanced equations represent the relative amounts of each substance involved in the reaction.