Question

Помогите решить.P→P₂O₅→H₃PO₄→K₃PO₄→Ca₃(PO₄)₂→H₃PO₄Na→NaOH→Na₂S→NaCl→Na₂SO₄→BaSO₄

Answer 1

1) P+O2=P2O; 2) P2O+H2O=H3PO4; 3) H3PO4+3KOH=K3PO4+3H2O 4) K3PO4+3CaCl=3KCl+Ca3(PO4)2; 5)не знаю 1)Na+H2O=NaOH 2)Na+H2S=Na2S+H2O 3)Na2S+CaCl2=NaCl +CaS 4)2NaCl+H2SO4=Na2SO4+2HCl 5)Na2SO4 +BACK(NO3)2=NaNO3 +BaSO4

Answer 2

The given sequence of chemical reactions represents a series of transformations involving different compounds. Let's break down each step and explain the reactions involved.

P → P₂O₅

The first reaction involves the transformation of elemental phosphorus (P) into diphosphorus pentoxide (P₂O₅). This reaction typically occurs when phosphorus reacts with excess oxygen. The balanced equation for this reaction is:

2P + 5O₂ → P₂O₅

P₂O₅ → H₃PO₄

The second reaction involves the conversion of diphosphorus pentoxide (P₂O₅) into phosphoric acid (H₃PO₄). This reaction occurs when P₂O₅ reacts with water (H₂O). The balanced equation for this reaction is:

P₂O₅ + 3H₂O → 2H₃PO₄

H₃PO₄ → K₃PO₄

The third reaction involves the formation of potassium phosphate (K₃PO₄) from phosphoric acid (H₃PO₄) and potassium hydroxide (KOH). The balanced equation for this reaction is:

3H₃PO₄ + 3KOH → K₃PO₄ + 3H₂O

K₃PO₄ → Ca₃(PO₄)₂

The fourth reaction involves the formation of calcium phosphate (Ca₃(PO₄)₂) from potassium phosphate (K₃PO₄) and calcium chloride (CaCl₂). The balanced equation for this reaction is:

2K₃PO₄ + 3CaCl₂ → Ca₃(PO₄)₂ + 6KCl

Ca₃(PO₄)₂ → H₃PO₄

The fifth reaction involves the conversion of calcium phosphate (Ca₃(PO₄)₂) back into phosphoric acid (H₃PO₄) by reacting it with sulfuric acid (H₂SO₄). The balanced equation for this reaction is:

Ca₃(PO₄)₂ + 3H₂SO₄ → 2H₃PO₄ + 3CaSO₄

H₃PO₄Na → NaOH

The sixth reaction involves the neutralization of phosphoric acid (H₃PO₄) with sodium hydroxide (NaOH) to form sodium phosphate (Na₃PO₄) and water (H₂O). The balanced equation for this reaction is:

H₃PO₄ + 3NaOH → Na₃PO₄ + 3H₂O