Question

К раствору содержащему 40 граммов сульфата меди 2 добавили 12 граммов железа, найти массу полученной соли..

Answer 1

CuSO₄ + Fe = Сu + FeSO₄

M(CuSO₄) = 64 + 32 + 16 * 4 = 160 г/моль
M(Fe) = 56 г/моль
M(Сu) = 64 г/моль
M(FeSO₄) = 56 + 32 + 16 * 4 = 152 г/моль

1) Определим, какое вещество в избытке
n(CuSO₄) = 40 : 160 = 0,25 моль
n(Fe) = 12 : 56 = 0,214 моль
по уравнению реакции с 1 моль CuSO₄ реагирует 1 моль Fe, следовательно
CuSO₄ - в избытке, расчет проведем по железу

2) Определим массы получившейся соли сульфата железа (II) 
m(FeSO₄) = (12 * 152 * 1) : (56 * 1) = 32,57 г

Answer 2

Calculation of the Mass of the Obtained Salt

To find the mass of the obtained salt, we need to determine the chemical equation for the reaction between copper sulfate (CuSO4) and iron (Fe). From the given information, we know that 40 grams of copper sulfate (CuSO4) and 12 grams of iron (Fe) were added to the solution.

The balanced chemical equation for the reaction between copper sulfate and iron is:

CuSO4 + Fe → FeSO4 + Cu

According to the equation, one mole of copper sulfate (CuSO4) reacts with one mole of iron (Fe) to produce one mole of iron sulfate (FeSO4) and one mole of copper (Cu).

To calculate the mass of the obtained salt (FeSO4), we need to determine the molar mass of iron sulfate (FeSO4). The molar mass of iron (Fe) is approximately 55.85 g/mol, and the molar mass of sulfur (S) is approximately 32.07 g/mol. Oxygen (O) has a molar mass of approximately 16.00 g/mol. Since there are four oxygen atoms in iron sulfate, we multiply the molar mass of oxygen by 4.

The molar mass of iron sulfate (FeSO4) is calculated as follows:

Molar mass of FeSO4 = (molar mass of Fe) + (molar mass of S) + (4 * molar mass of O) = (55.85 g/mol) + (32.07 g/mol) + (4 * 16.00 g/mol) = 55.85 g/mol + 32.07 g/mol + 64.00 g/mol = 151.92 g/mol

Now, we can calculate the number of moles of iron sulfate (FeSO4) produced:

Number of moles of FeSO4 = (mass of FeSO4) / (molar mass of FeSO4) = (mass of FeSO4) / (151.92 g/mol)

Given that 12 grams of iron (Fe) were added, we can substitute this value into the equation:

Number of moles of FeSO4 = (12 g) / (151.92 g/mol)

Finally, we can calculate the mass of the obtained salt (FeSO4) by multiplying the number of moles of FeSO4 by its molar mass:

Mass of obtained salt (FeSO4) = (number of moles of FeSO4) * (molar mass of FeSO4)

Let's calculate the mass of the obtained salt using the given values.

Calculation:

Number of moles of FeSO4 = (12 g) / (151.92 g/mol) = 0.0789 mol

Mass of obtained salt (FeSO4) = (0.0789 mol) * (151.92 g/mol) = 11.98 g

Therefore, the mass of the obtained salt is approximately 11.98 grams.