
Составить электронные уравнения.Раставить коэффициенты в уравнениях реакции и указать что
востановитель,а что окисилитель.P+HIO3+H2O=H3PO4+HI

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Balancing the Chemical Equation
The given chemical equation is: P + HIO3 + H2O = H3PO4 + HI.To balance this chemical equation, we can follow these steps:
1. Balance the atoms of each element one at a time. 2. Start by balancing the least common atom or the atom that appears in the fewest reactants and products.
Balancing the Equation Step by Step
1. Balance Phosphorus (P): - There is 1 P on the left side and 1 P on the right side. Phosphorus is already balanced.2. Balance Iodine (I): - There is 1 I in HIO3 and 1 I in HI on the left side, and 1 I in H3PO4 on the right side. - To balance I, we can add a coefficient of 5 in front of HI on the right side.
3. Balance Hydrogen (H): - There are 3 H in HIO3 and 1 H in H2O on the left side, and 3 H in H3PO4 and 1 H in HI on the right side. - To balance H, we can add a coefficient of 3 in front of H2O on the left side.
4. Balance Oxygen (O): - There are 3 O in HIO3 and 1 O in H2O on the left side, and 4 O in H3PO4 on the right side. - To balance O, we can add a coefficient of 2 in front of HIO3 on the left side.
Balanced Chemical Equation
The balanced chemical equation is: P + 5HIO3 + 3H2O = H3PO4 + 5HIIdentifying the Oxidizing and Reducing Agents
In the given reaction, the substance that undergoes oxidation is the reducing agent, and the substance that undergoes reduction is the oxidizing agent.- Oxidizing Agent: The substance that gets reduced is the oxidizing agent. - Reducing Agent: The substance that gets oxidized is the reducing agent.
In the balanced equation P + 5HIO3 + 3H2O = H3PO4 + 5HI, P is the reducing agent, and HIO3 is the oxidizing agent.
This information is based on the chemical properties and the changes in oxidation states of the elements involved in the reaction.
I hope this helps! If you have further questions, feel free to ask.


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