Question

Какая масса оксида получится при взаимодействии 130 г цинка с кислородом

Answer 1

Количество вещества (n) некоторые обозначают буквой "ню" v

Answer 2

Calculating the Mass of Oxide Produced

When zinc reacts with oxygen, it forms zinc oxide. To calculate the mass of the zinc oxide produced when 130 g of zinc reacts with oxygen, we can use the balanced chemical equation for the reaction.

The balanced chemical equation for the reaction between zinc and oxygen is:

2 Zn + O2 → 2 ZnO

According to the balanced chemical equation, 2 moles of zinc react with 1 mole of oxygen to produce 2 moles of zinc oxide.

To find the mass of zinc oxide produced, we can use the molar masses of zinc (Zn) and oxygen (O) to calculate the mass of zinc oxide produced when 130 g of zinc reacts with oxygen.

The molar mass of zinc (Zn) is approximately 65.38 g/mol. The molar mass of oxygen (O) is approximately 16.00 g/mol.

Calculation

1. Calculate the moles of zinc: - Moles of zinc = Mass of zinc / Molar mass of zinc - Moles of zinc = 130 g / 65.38 g/mol - Moles of zinc = 1.988 moles

2. Calculate the moles of oxygen: - According to the balanced chemical equation, 2 moles of zinc react with 1 mole of oxygen. - Moles of oxygen = Moles of zinc / 2 - Moles of oxygen = 1.988 moles / 2 - Moles of oxygen = 0.994 moles

3. Calculate the mass of zinc oxide produced: - Mass of zinc oxide = Moles of zinc oxide * Molar mass of zinc oxide - Molar mass of zinc oxide = Molar mass of zinc + Molar mass of oxygen - Molar mass of zinc oxide = 65.38 g/mol + 16.00 g/mol - Molar mass of zinc oxide = 81.38 g/mol - Mass of zinc oxide = 0.994 moles * 81.38 g/mol - Mass of zinc oxide = 80.89 g

Conclusion

When 130 g of zinc reacts with oxygen, the mass of zinc oxide produced is approximately 80.89 grams.