Question

Чи вистачить хлору об’ємом 44,8 л для повного заміщення Гідрогену в метані об’ємом 5,6 л(н.у.)?

Answer 1

чи вистачить хлору об’ємом 44,8 л для повного заміщення Гідрогену в метані об’ємом 5,6 л(н.у.)?
1. При заміщенні одного атома гідрогену потрібно один атом хлору, відповідно  відношення відповідно 1:1 на 5,6 потрібно 5,6, а хлору 44,8/5,6= 8, потрібно для повного заміщенння 22,4 л Вистачить!

Answer 2

Calculation of Chlorine Volume Needed to Replace Hydrogen in Methane

To calculate whether 44.8 liters of chlorine is sufficient to completely replace the hydrogen in 5.6 liters of methane (at standard temperature and pressure), we can use the balanced chemical equation for the reaction between chlorine and methane.

The balanced chemical equation for the reaction is: CH4 + Cl2 → CH3Cl + HCl

From the balanced equation, we can see that 1 mole of methane reacts with 1 mole of chlorine to produce 1 mole of chloromethane and 1 mole of hydrogen chloride.

Calculation Steps

1. Calculate the moles of methane: - Using the ideal gas law, we can calculate the moles of methane: - n = PV/RT - Where: - P = pressure (at standard temperature and pressure, P = 1 atm) - V = volume of methane (5.6 L) - R = ideal gas constant (0.0821 L·atm/(K·mol)) - T = temperature (at standard temperature and pressure, T = 273 K) - Substituting the values: - n(CH4) = (1 atm * 5.6 L) / (0.0821 L·atm/(K·mol) * 273 K) - n(CH4) ≈ 0.24 moles

2. Calculate the moles of chlorine needed: - From the balanced chemical equation, we know that 1 mole of methane reacts with 1 mole of chlorine. - Therefore, the moles of chlorine needed is also 0.24 moles.

3. Calculate the volume of chlorine needed: - Using the ideal gas law, we can calculate the volume of chlorine needed: - V = nRT/P - Where: - n = moles of chlorine needed (0.24 moles) - R = ideal gas constant (0.0821 L·atm/(K·mol)) - T = temperature (at standard temperature and pressure, T = 273 K) - P = pressure (at standard temperature and pressure, P = 1 atm) - Substituting the values: - V(Cl2) = (0.24 moles * 0.0821 L·atm/(K·mol) * 273 K) / 1 atm - V(Cl2) ≈ 5.7 L

Conclusion

Based on the calculations, approximately 5.7 liters of chlorine are needed to completely replace the hydrogen in 5.6 liters of methane at standard temperature and pressure. Therefore, 44.8 liters of chlorine would be more than sufficient for this reaction.