Question

Смешали 40 литров бутана и 400 литров кислорода. Какой газ в каком количестве останется, и какой объём углекислого газа выделится?

Answer 1

     40               х              y
2C4H10 + 13O2 -> 8CO2 + 10H2O
      2              13           8
40 - x
2 - 13
x=260л- О2 необходимо, О2 в избытке.
40 - y
2 - 8
y=160л СО2

Answer 2

Calculating Remaining Gases and Carbon Dioxide Produced

To calculate the remaining gases and the volume of carbon dioxide produced when 40 liters of butane and 400 liters of oxygen are mixed, we can use the following chemical equation:

2 C4H10 + 13 O2 → 8 CO2 + 10 H2O

From the equation, we can see that 2 moles of butane react with 13 moles of oxygen to produce 8 moles of carbon dioxide and 10 moles of water.

Using the ideal gas law, we can calculate the amount of gases remaining and the volume of carbon dioxide produced.

Calculation

1. Moles of Butane and Oxygen: - Moles of butane = Volume of butane / molar volume of butane - Moles of oxygen = Volume of oxygen / molar volume of oxygen

2. Limiting Reactant: - Determine the limiting reactant by comparing the moles of butane and oxygen.

3. Remaining Gases: - Calculate the moles of the excess reactant (the reactant that is not limiting). - Convert the moles of the excess reactant to volume using the molar volume of the gas.

4. Volume of Carbon Dioxide Produced: - Calculate the moles of carbon dioxide produced using the stoichiometry of the reaction. - Convert the moles of carbon dioxide to volume using the molar volume of the gas.

Results

The specific calculations and results will depend on the molar volumes of butane, oxygen, and carbon dioxide, as well as the limiting reactant. The molar volumes of gases are typically provided at standard temperature and pressure (STP), which is 0°C and 1 atm pressure.

Given the complexity of the calculations and the need for specific molar volumes, it's recommended to use a chemical equation calculator or a stoichiometry calculator to obtain the precise results.