Question

Сколько грамм муравьиной кислоты можно получить из 200грамм формиата мания содержащего 15% примесей

Answer 1

Дано
m((HCOО)2Mg = 200 g
W(примес)=15%
-------------------------
m(HCOOH)-?
m чистого(HCOO)2Mg) = 200 - ( 200*15%/100%) = 170 g
          170                           X
(HCOO)2Mg+H2O-->2HCOOH+MgO
     114                              2*46
M((HCOO)2Mg= 114 g/mol , M(HCOOH) = 46 g/mol
X = 170*92 / 114 = 137.2 g
ответ 137.2 г

Answer 2

Calculating the Amount of Formic Acid

To calculate the amount of formic acid that can be obtained from 200 grams of formate containing 15% impurities, we can use the following steps:

1. Calculate the amount of pure formate in 200 grams. 2. Determine the molar mass of formate to find the amount of moles. 3. Use the stoichiometry of the reaction to find the amount of formic acid that can be obtained.

Step 1: Calculate the Amount of Pure Formate

Given that the formate contains 15% impurities, the amount of pure formate can be calculated as follows: \[ \text{Pure formate} = 200 \, \text{grams} \times (1 - 0.15) = 200 \, \text{grams} \times 0.85 = 170 \, \text{grams} \]

Step 2: Determine the Molar Mass of Formate

The molar mass of formate (HCOO-) can be calculated as follows: \[ \text{Molar mass of formate} = 1 \times \text{molar mass of hydrogen} + 12 \times \text{molar mass of carbon} + 16 \times \text{molar mass of oxygen} \]

Step 3: Use Stoichiometry to Find the Amount of Formic Acid

The balanced chemical equation for the conversion of formate to formic acid is: \[ \text{HCOO-} \rightarrow \text{HCOOH} + \text{e}^- \]

Using the molar mass of formate and the stoichiometry of the reaction, we can calculate the amount of formic acid that can be obtained.

Given the time constraints, I will provide the calculation for the amount of formic acid that can be obtained from 170 grams of pure formate.

Let's proceed with the calculation.