Вопрос задан 24.02.2019 в 20:55. Предмет Химия. Спрашивает Yermakov Artemik.

Реакции в растворах электролитов: NaOH+Zn(NO3)2= CuSO4+NaOH= Если не трудно, решите пожалуйста)

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Отвечает Кибешова Алиса.
=2NaNO3+Zn(OH)2
=Cu(OH)2+Na2SO4
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Reactions in Electrolyte Solutions

When electrolytes dissolve in water, they dissociate into ions, which are charged particles. These ions can then undergo various reactions in the solution. Let's examine the reactions of the given electrolyte solutions: NaOH, Zn(NO3)2, and CuSO4.

Reaction 1: NaOH

When sodium hydroxide (NaOH) dissolves in water, it dissociates into sodium ions (Na+) and hydroxide ions (OH-). The reaction can be represented as follows:

NaOH(s) → Na+(aq) + OH-(aq)

Reaction 2: Zn(NO3)2

Zinc nitrate (Zn(NO3)2) is also an electrolyte that dissociates into zinc ions (Zn2+) and nitrate ions (NO3-) when dissolved in water. The reaction can be represented as follows:

Zn(NO3)2(s) → Zn2+(aq) + 2NO3-(aq)

Reaction 3: CuSO4

Copper sulfate (CuSO4) is another electrolyte that dissociates into copper ions (Cu2+) and sulfate ions (SO42-) when dissolved in water. The reaction can be represented as follows:

CuSO4(s) → Cu2+(aq) + SO42-(aq)

Reaction: NaOH + Zn(NO3)2

When sodium hydroxide (NaOH) is added to zinc nitrate (Zn(NO3)2) solution, a double displacement reaction occurs. The hydroxide ions (OH-) from NaOH react with the zinc ions (Zn2+) from Zn(NO3)2 to form zinc hydroxide (Zn(OH)2) as a precipitate. The sodium ions (Na+) and nitrate ions (NO3-) remain in the solution. The reaction can be represented as follows:

2NaOH(aq) + Zn(NO3)2(aq) → Zn(OH)2(s) + 2NaNO3(aq)

Reaction: CuSO4 + NaOH

When copper sulfate (CuSO4) is added to sodium hydroxide (NaOH) solution, a double displacement reaction also occurs. The hydroxide ions (OH-) from NaOH react with the copper ions (Cu2+) from CuSO4 to form copper hydroxide (Cu(OH)2) as a precipitate. The sodium ions (Na+) and sulfate ions (SO42-) remain in the solution. The reaction can be represented as follows:

CuSO4(aq) + 2NaOH(aq) → Cu(OH)2(s) + Na2SO4(aq)

Solving the Equations

To solve the equations, we need to balance them by ensuring that the number of atoms of each element is the same on both sides of the equation. Here are the balanced equations for the reactions:

1. NaOH + Zn(NO3)2 → Zn(OH)2 + 2NaNO3 2. CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4

Please note that these equations represent the overall reaction and may not necessarily reflect the actual step-by-step mechanism of the reaction.

I hope this helps! Let me know if you have any further questions.

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