Question

вещества образующие осадок при взаимодействии с раствором серной кислоты

Answer 1

 С раствором серной кислоты образуют осадок соединения бария, кальция, стронция, серебра и свинца.
Например, 
H₂SO₄ + Ca(OH)₂ = CaSO₄↓ + 2H₂O
H₂SO₄ + Sr(OH)₂ = SrSO₄↓ + 2H₂O
H₂SO₄ + BaCI₂ = BaSO₄↓ + 2HCI
H₂SO₄ + Pb(NO₃)₂ = PbSO₄↓ + 2HNO₃

Answer 2

Substances Forming Precipitate When Reacting with Sulfuric Acid Solution

When sulfuric acid reacts with certain substances, it can lead to the formation of precipitates. Some of the substances that form precipitates when reacting with sulfuric acid solution include:

1. Barium Chloride (BaCl2) - When barium chloride reacts with sulfuric acid, it forms barium sulfate as a precipitate. - The chemical equation for this reaction is: BaCl2 + H2SO4 → BaSO4 + 2HCl.

2. Copper (Cu) - Copper can form a precipitate when it reacts with sulfuric acid. - The chemical equation for this reaction is: 8HNO3 + 3Cu = 3Cu(NO3)2 + 2NO + 4H2O.

3. Sodium Nitrate (NaNO3) - Sodium nitrate can also form a precipitate when it reacts with sulfuric acid. - The chemical equation for this reaction is not provided in the search results.

These are some of the substances that form precipitates when reacting with sulfuric acid solution.