Question

Решите ионное уравнение хлорид натрия и нитрат свинца

Answer 1

2NaCl + Pb(NO3)2 = PbCl2 + 2NaNO3
$2Na^+ + 2Cl^- + Pb^{2+} + 2NO_3^- = 2Na^+ + 2NO_3^- + PbCl_2 \\ 2Cl^- + Pb^{2+} = PbCl_2$

Answer 2

Solving the Ionic Equation for Sodium Chloride and Lead Nitrate

To solve the ionic equation for the reaction between sodium chloride (NaCl) and lead nitrate (Pb(NO3)2), we need to first write the balanced molecular equation and then separate the soluble ionic compounds into their respective ions.

Step 1: Writing the Balanced Molecular Equation The balanced molecular equation for the reaction between sodium chloride and lead nitrate is: ``` 2NaCl + Pb(NO3)2 → 2NaNO3 + PbCl2 ```

Step 2: Separating the Soluble Ionic Compounds into Ions In the balanced molecular equation, sodium chloride and lead nitrate are both soluble ionic compounds. When they dissociate in water, they form ions. The dissociation of these compounds is as follows: - Sodium chloride (NaCl): NaCl → Na⁺ + Cl⁻ - Lead nitrate (Pb(NO3)2): Pb(NO3)2 → Pb²⁺ + 2NO3⁻

Step 3: Writing the Ionic Equation Using the ions formed from the dissociation of the soluble ionic compounds, the ionic equation for the reaction between sodium chloride and lead nitrate is: ``` 2Na⁺ + 2Cl⁻ + Pb²⁺ + 2NO3⁻ → 2Na⁺ + 2NO3⁻ + PbCl2 ``` Simplifying the equation by removing the spectator ions (ions that appear on both sides of the equation), we get: ``` 2Cl⁻ + Pb²⁺ → PbCl2 ``` This is the ionic equation for the reaction between sodium chloride and lead nitrate.

Conclusion

The ionic equation for the reaction between sodium chloride and lead nitrate is 2Cl⁻ + Pb²⁺ → PbCl2. This equation represents the chemical reaction at the ionic level, showing the formation of lead chloride from the interaction of the ions.