Question

2HCL+Mg=MgCl2+H2 Образовался водород химическим количеством 0.450 моль. Опредилите химическое количество HCl, вступившего в реакцию

Answer 1

Если я не ошибаюсь, все очень просто .2HCL+Mg=MgCl2+H2. делаем пропорцию по HCl и H2.
Х моль ашхлор-0.45 моль водорода
2 моль ашхлор-1 моль водорода
Х= 0.45*2/1=0.9 моль аш хлор

Answer 2

Chemical Equation and Given Information

The chemical equation provided is: 2HCl + Mg = MgCl2 + H2. It is mentioned that 0.450 moles of hydrogen gas were formed in the reaction.

Calculating the Chemical Quantity of HCl

To determine the chemical quantity of HCl that reacted, we can use the stoichiometry of the balanced chemical equation. According to the balanced equation, 2 moles of HCl react to produce 1 mole of H2. Therefore, to find the moles of HCl that reacted, we can use the following calculation:

0.450 moles of H2 (formed) × (2 moles of HCl / 1 mole of H2) = 0.900 moles of HCl

So, the chemical quantity of HCl that reacted in the given reaction is 0.900 moles.

This calculation is based on the stoichiometry of the balanced chemical equation, where 2 moles of HCl react to produce 1 mole of H2 .