Question

Рассмотреть реакции как окислительно восстановительныеNa+HClFe+CuSO4

Answer 1

0        +1-2      +1-2+1    0
2Na + 2H2O = 2NaOH + H2↑
2| Na[0]  -1e  = Na[+1]        |  восстановитель, окисление
1| 2H[+1]  +2e  = H2[0]    | окислитель, восстановление 

0      +2+6-2    +2+6-2    0
Fe + CuSO4 = FeSO4 + Cu
1| Fe[0]  -2e  = Fe[+2]        |  восстановитель, окисление
1| Cu[+2]  +2e  = Cu[0]    | окислитель, восстановление              
Примечание: в квадратных скобках указана степень окисления элемента

Answer 2

Oxidation-Reduction Reactions of Na, HCl, Fe, and CuSO4

Sodium (Na) and Hydrochloric Acid (HCl): When sodium reacts with hydrochloric acid, it undergoes a single displacement reaction, where the sodium displaces hydrogen from the hydrochloric acid to form sodium chloride and hydrogen gas. The balanced chemical equation for this reaction is:

2Na(s) + 2HCl(aq) → 2NaCl(aq) + H2(g) [[1]]

Iron (Fe) and Copper(II) Sulfate (CuSO4): When iron reacts with copper(II) sulfate, it undergoes a displacement reaction as well. The iron displaces copper from the copper(II) sulfate to form iron(II) sulfate and copper. The balanced chemical equation for this reaction is:

Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s) [[2]]

Overall, these reactions involve the transfer of electrons from one substance to another, leading to changes in oxidation states and the formation of new compounds.

Is there anything else you would like to know about these reactions or any other topic?