Question

Дописати рівняння реакцій (дописати ,а потім урівняти ) CuH9OH+O2 -> CH3COOH +MgO-> C3H7OH+K->

Answer 1

CuH9OH -  такого соединения нет
2CH3COOH +MgO-> (СH3COO)2Mg + H2O
2C3H7OH +2K-> 2C3H7OK + H2

Answer 2

Balancing Chemical Equations

To balance the chemical equations provided, we'll start by writing out the unbalanced equations and then proceed to balance them.

1. CuH9OH + O2 -> CH3COOH 2. MgO -> C3H7OH + K

Balancing the Equations

Let's balance the equations step by step.

1. CuH9OH + O2 -> CH3COOH

This equation represents the combustion of CuH9OH (a hypothetical compound) to produce CH3COOH (acetic acid) and water. To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

The balanced equation is: ``` CuH9OH + 8O2 -> 3CH3COOH + 4H2O ```

2. MgO -> C3H7OH + K

This equation represents the reaction of MgO (magnesium oxide) with an unknown compound to produce C3H7OH (isopropyl alcohol) and K (potassium). To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

The balanced equation is: ``` 3MgO -> C3H7OH + 3K ```

Final Balanced Equations

After balancing the equations, the final balanced chemical equations are:

1. CuH9OH + 8O2 -> 3CH3COOH + 4H2O 2. 3MgO -> C3H7OH + 3K

These balanced equations ensure that the law of conservation of mass is satisfied, with the same number of atoms of each element on both sides of the equations.