Question

Используя метод электронного баланса, расставьте коэффициенты в окислительно-восстановительной реакции. Укажите окислитель и восстановитель. KJ+Cu(NO3)2-CuJ+J2+KNO3

Answer 1

4 KI + 2 Cu(NO3)2 = 2 CuI + I2 + 4 KNO3
2I(-) - 2e = I2(0)/1/восстановитель, окислился
Cu(+2) + 1e= Cu(+)/2/окислитель, восстановился

Answer 2

Balancing the Redox Reaction using the Electron Balance Method

To balance the given redox reaction using the electron balance method, we need to assign oxidation numbers to each element in the reaction and then balance the number of electrons transferred.

The given reaction is: KJ + Cu(NO3)2 → CuJ + J2 + KNO3

Let's start by assigning oxidation numbers to each element in the reaction:

- The oxidation number of K is +1. - The oxidation number of J is -1. - The oxidation number of Cu in Cu(NO3)2 is +2. - The oxidation number of N in NO3 is -2, so the oxidation number of N in Cu(NO3)2 is also -2. - The oxidation number of O in NO3 is -2, so the oxidation number of O in Cu(NO3)2 is also -2.

Now, let's determine the changes in oxidation numbers for the elements that undergo oxidation and reduction:

- K changes from 0 to +1, so it is oxidized. - Cu changes from +2 to 0, so it is reduced. - J changes from 0 to -1, so it is reduced. - N changes from -2 to +5, so it is oxidized. - O changes from -2 to 0, so it is reduced.

To balance the number of electrons transferred, we need to multiply the half-reactions by appropriate coefficients so that the total number of electrons gained in the reduction half-reaction is equal to the total number of electrons lost in the oxidation half-reaction.

The oxidation half-reaction is: 2J- → J2 + 2e-

The reduction half-reaction is: Cu2+ + 2e- → Cu

To balance the number of electrons, we need to multiply the oxidation half-reaction by 2 and the reduction half-reaction by 1:

2J- → J2 + 2e- Cu2+ + 2e- → Cu

Now, let's combine the two half-reactions:

2J- + Cu2+ → J2 + Cu

Finally, let's balance the remaining atoms in the reaction:

2KJ + Cu(NO3)2 → 2CuJ + J2 + 2KNO3

Therefore, the balanced equation for the given redox reaction is: 2KJ + Cu(NO3)2 → 2CuJ + J2 + 2KNO3

In this reaction, KJ is the oxidizing agent (it is being reduced) and Cu(NO3)2 is the reducing agent (it is being oxidized).

Please note that the above explanation is based on the electron balance method and the information provided.