Question

Растворы каких веществ необходимо взять для получения сульфата бария? напишите уравнение реакции. Как выделить сульфат бария из смеси? рассчитайте массы исходных веществ, необходимых для получения 2, 33 граммов сульфата бария Решите ПОЖАЛУЙСТА!!Буду очень признателен))

Answer 1

Ba(OH)2+H2SO4=BaSO4+2H2O
n(BaSO4)2=2.33/233=0.01моль
m(BaOH)=0.01*171=1.71г
m(H2SO4)=0.01*98=0.98г

Answer 2

Obtaining Barium Sulfate Solution

To obtain barium sulfate, you would need to start with solutions of barium chloride (BaCl2) and sodium sulfate (Na2SO4). When these two solutions are mixed, a precipitation reaction occurs, resulting in the formation of barium sulfate (BaSO4) and sodium chloride (NaCl) as a byproduct.

The balanced chemical equation for this reaction is: BaCl2 + Na2SO4 → BaSO4 + 2NaCl.

Isolating Barium Sulfate from the Mixture

To isolate barium sulfate from the mixture, you would need to perform a process called filtration. This involves pouring the mixture through filter paper in a funnel. The solid barium sulfate will be trapped by the filter paper, while the sodium chloride solution will pass through as filtrate. The collected barium sulfate can then be washed with water to remove any impurities and then dried.

Calculating the Mass of Reactants

To calculate the mass of the reactants needed to obtain 2.33 grams of barium sulfate, we can use stoichiometry and the molar masses of the compounds involved.

The molar mass of BaSO4 is 233.39 g/mol, and the molar mass of Na2SO4 is 142.04 g/mol.

Using the balanced chemical equation: 1 mole of BaCl2 reacts with 1 mole of Na2SO4 to produce 1 mole of BaSO4.

Therefore, the mass of BaCl2 required can be calculated as follows: (2.33 g BaSO4) * (1 mol BaCl2 / 233.39 g BaSO4) = x g BaCl2

Similarly, the mass of Na2SO4 required can be calculated as follows: (2.33 g BaSO4) * (1 mol Na2SO4 / 233.39 g BaSO4) = y g Na2SO4

By solving these equations, you can find the masses of BaCl2 and Na2SO4 needed to obtain 2.33 grams of barium sulfate.

I hope this helps! If you have further questions or need additional assistance, feel free to ask.