Question

Сколько граммов алюминия необходимо взять чтобы получить 170 грамм сульфата алюминия

Answer 1

26 треба .........походу

Answer 2

Calculating the Amount of Aluminum Needed to Obtain 170 Grams of Aluminum Sulfate

To calculate the amount of aluminum needed to obtain 170 grams of aluminum sulfate, we can use the chemical equation for the reaction between aluminum and sulfuric acid to produce aluminum sulfate. The balanced chemical equation for this reaction is:

2Al + 3H2SO4 → Al2(SO4)3 + 3H2

From the balanced chemical equation, we can see that 2 moles of aluminum react with 3 moles of sulfuric acid to produce 1 mole of aluminum sulfate. We can use this information to calculate the amount of aluminum needed to obtain 170 grams of aluminum sulfate.

Using the molar mass of aluminum sulfate (Al2(SO4)3) and aluminum, we can calculate the amount of aluminum required.

The molar mass of aluminum sulfate (Al2(SO4)3) is approximately 342.15 g/mol. The molar mass of aluminum (Al) is approximately 26.98 g/mol.

Calculation:

1. Calculate the molar mass of aluminum sulfate: - Molar mass of Al2(SO4)3 = 2(Al) + 3(S) + 12(O) = 2(26.98) + 3(32.07) + 12(16.00) = 342.15 g/mol.

2. Calculate the amount of aluminum needed to obtain 170 grams of aluminum sulfate: - Using the molar mass of aluminum sulfate, we can calculate the moles of aluminum sulfate present in 170 grams. - Moles of Al2(SO4)3 = Mass / Molar mass = 170 g / 342.15 g/mol = 0.497 moles.

3. Using the stoichiometry of the reaction, we find the moles of aluminum required: - From the balanced chemical equation, 2 moles of aluminum react to produce 1 mole of aluminum sulfate. - Moles of Al = 0.497 moles / 1 * 2 = 0.994 moles.

4. Convert moles of aluminum to grams: - Mass of aluminum = Moles * Molar mass = 0.994 moles * 26.98 g/mol = 26.81 grams.

Therefore, approximately 26.81 grams of aluminum are needed to obtain 170 grams of aluminum sulfate.

Conclusion:

Based on the calculations, approximately 26.81 grams of aluminum are needed to obtain 170 grams of aluminum sulfate through the reaction of aluminum with sulfuric acid.

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