Question

Рассчитайте количество вещества ацетилена, который потребуется для получения 5.6л бензола

Answer 1

Ответ:

Реакция тримеризации ацетилена идёт по схеме:

3C2H2 = C6H6

Рассчитаем количество бензола по объему:

n = V/Vm (n - количество веществ, V - объем вещества, Vm - молярный объем - константа)

Vm = 22.4 л/моль

n(С6Н6) = 5.6/22.4 = 0.25 моль

Коэффициент ацетилена в 3 раза больше коэффициента бензола (см схему реакции), значит количество ацителена в 3 раза больше:

n(C2H2) = 0.25*3 = 0.75 моль

Ответ : 0.75 моль

Answer 2

Calculating the Amount of Acetylene Required to Produce 5.6L of Benzene

To calculate the amount of acetylene needed to produce 5.6L of benzene, we can use the balanced chemical equation for the reaction between acetylene and benzene. The balanced chemical equation for the reaction is:

2C2H2 + 5H2 → C6H6

This equation shows that 2 moles of acetylene (C2H2) react to produce 1 mole of benzene (C6H6). From this equation, we can determine the amount of acetylene needed to produce 5.6L of benzene.

Calculation:

Given: Volume of benzene (C6H6) = 5.6L Molar ratio of acetylene to benzene = 2:1

Using the ideal gas law, we can convert the volume of benzene to moles and then determine the amount of acetylene required.

The molar volume of a gas at standard temperature and pressure (STP) is approximately 22.4L/mol.

Step 1: Convert the volume of benzene to moles: - Moles of benzene = Volume of benzene / Molar volume at STP - Moles of benzene = 5.6L / 22.4L/mol - Moles of benzene = 0.25 moles

Step 2: Determine the moles of acetylene required: - Moles of acetylene = 2 * Moles of benzene - Moles of acetylene = 2 * 0.25 moles - Moles of acetylene = 0.5 moles

Therefore, 0.5 moles of acetylene are required to produce 5.6L of benzene.