Question

Разобрать окислительно-восстановительные реакции, указать окислитель, восстановитель, составить электронный баланс Цинк +соляная кислота Оксид меди(II) + водород Сульфид железа(II) + кислород=оксид серы(IV)+оксид железа(III)

Answer 1

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Answer 2

Understanding Oxidation-Reduction Reactions

Oxidation-reduction (redox) reactions involve the transfer of electrons between reactants. In these reactions, one substance loses electrons (oxidation) while another gains electrons (reduction). Let's break down the given redox reaction and identify the oxidizing agent, reducing agent, and balance the electron transfer.

Given Redox Reaction:

The given redox reaction is: Zn + 2HCl → ZnCl2 + H2 This can be broken down into oxidation and reduction half-reactions.

Oxidation Half-Reaction:

The oxidation half-reaction involves the loss of electrons. In this case, zinc (Zn) is oxidized to zinc chloride (ZnCl2), and the electrons are on the product side. The oxidation half-reaction is: Zn → Zn^2+ + 2e^-

Reduction Half-Reaction:

The reduction half-reaction involves the gain of electrons. In this case, hydrogen ions (H^+) are reduced to form hydrogen gas (H2). The reduction half-reaction is: 2H^+ + 2e^- → H2

Electron Balance:

To balance the electron transfer, the oxidation and reduction half-reactions are multiplied by appropriate coefficients to ensure that the electrons lost in the oxidation half-reaction are equal to the electrons gained in the reduction half-reaction.

Multiplying the reduction half-reaction by 2 to balance the electrons gives: 2H^+ + 2e^- → H2

Overall Balanced Redox Reaction:

The overall balanced redox reaction is obtained by adding the balanced oxidation and reduction half-reactions together: Zn + 2H^+ → Zn^2+ + H2

This balanced redox reaction represents the chemical reaction between zinc and hydrochloric acid to produce zinc chloride and hydrogen gas.

I hope this breakdown helps in understanding the oxidation-reduction reactions and the electron balance in the given chemical reaction! If you have further questions or need more explanations, feel free to ask.