Question

Найти m(NH3) -? v(NH3) -? N(NH3) -? v в примере N2+3H2=2NH3 дано v(N2) =0,5 моль​

Answer 1

Ответ:

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Объяснение:

Answer 2

Calculation of m(NH3):

To find the molar mass of NH3 (ammonia), we need to calculate the sum of the atomic masses of its constituent elements.

The atomic mass of nitrogen (N) is approximately 14.01 g/mol, and the atomic mass of hydrogen (H) is approximately 1.01 g/mol.

Since ammonia (NH3) consists of one nitrogen atom and three hydrogen atoms, we can calculate the molar mass as follows:

m(NH3) = (1 * m(N)) + (3 * m(H))

m(NH3) = (1 * 14.01 g/mol) + (3 * 1.01 g/mol)

m(NH3) = 14.01 g/mol + 3.03 g/mol

m(NH3) = 17.04 g/mol

Therefore, the molar mass of NH3 (ammonia) is approximately 17.04 g/mol.

Calculation of v(NH3):

To find the volume of NH3 (ammonia) produced in the given reaction, we need to use the stoichiometry of the balanced equation.

The balanced equation is: N2 + 3H2 → 2NH3

From the balanced equation, we can see that 1 mole of N2 reacts to produce 2 moles of NH3.

Given that v(N2) = 0.5 mol, we can calculate the volume of NH3 produced as follows:

v(NH3) = (2 * v(N2)) / 1

v(NH3) = (2 * 0.5 mol) / 1

v(NH3) = 1 mol

Therefore, the volume of NH3 (ammonia) produced in the given reaction is 1 mol.

Calculation of N(NH3):

To find the number of moles of NH3 (ammonia) produced in the given reaction, we can use the stoichiometry of the balanced equation.

From the balanced equation: N2 + 3H2 → 2NH3

We can see that 1 mole of N2 reacts to produce 2 moles of NH3.

Given that v(N2) = 0.5 mol, we can calculate the number of moles of NH3 produced as follows:

N(NH3) = (2 * v(N2)) / 1

N(NH3) = (2 * 0.5 mol) / 1

N(NH3) = 1 mol

Therefore, the number of moles of NH3 (ammonia) produced in the given reaction is 1 mol.

Summary:

- m(NH3) (molar mass of NH3) is approximately 17.04 g/mol. - v(NH3) (volume of NH3 produced) is 1 mol. - N(NH3) (number of moles of NH3 produced) is 1 mol.

Please note that the calculations provided are based on the given information and the stoichiometry of the balanced equation.