Question

Перетворіть напівсхеми на рівняння та розмістіть їх за зростанням суми коефіцієнтів A) CH3+NH2 + O2 - Б) CH3+NH2 + HCl - B) CH3+NH2 + H2SO4 - Г) CH3+NH2 + H3PO4 -

Answer 1

А) 4CH3NH2 + 9O2 → 4CO2 + 10H2O + 2N2

Б) CH3NH2 + HCl → (CH3NH3)Cl

В) 2CH3NH2 + H2SO4 → (CH3NH3)2SO4

Г) 3CH3NH2 + H3PO4 → 3CH3NH3 + PO4

Answer 2

Conversion of Half-Reactions to Equations

To convert the given half-reactions into equations, we need to balance the number of atoms and charges on both sides of the reaction. Here are the conversions for each half-reaction:

A) CH3NH2 + O2 ->

The half-reaction for the oxidation of CH3NH2 can be written as:

CH3NH2 ->

To balance the equation, we need to add water (H2O) and hydrogen ions (H+) to the right side:

CH3NH2 -> CO2 + H2O + 2H+ + 2e-

B) CH3NH2 + HCl ->

The half-reaction for the oxidation of CH3NH2 can be written as:

CH3NH2 ->

To balance the equation, we need to add water (H2O) and hydrogen ions (H+) to the right side:

CH3NH2 -> CO2 + H2O + 2H+ + 2e-

C) CH3NH2 + H2SO4 ->

The half-reaction for the oxidation of CH3NH2 can be written as:

CH3NH2 ->

To balance the equation, we need to add water (H2O) and hydrogen ions (H+) to the right side:

CH3NH2 -> CO2 + H2O + 2H+ + 2e-

D) CH3NH2 + H3PO4 ->

The half-reaction for the oxidation of CH3NH2 can be written as:

CH3NH2 ->

To balance the equation, we need to add water (H2O) and hydrogen ions (H+) to the right side:

CH3NH2 -> CO2 + H2O + 2H+ + 2e-

Please note that the equations provided above are the balanced equations for the oxidation of CH3NH2 in each case.