Question

Сколько молекул содержится в смеси из 0,2 моля азота, 1,5 моля кислорода и 0,3 моля газообразного водорода и какой объем эта смесь занимает при нормальных условиях?помогите даю 20 баллов

Answer 1

Ответ:

V  = 44,8 литра

N = 12*10²³ молекул

Объяснение:

∑n = n(N₂) + n(O₂) + n(HCl)

∑n = 0,2 + 1,5 + 0,3 = 2моль

V = n*Vm = 2моль * 22,4 л/моль = 44,8 литра

N = n* N(A) = 2моль * 6*10²³ молекул/моль = 12*10²³ молекул

Answer 2

Calculating the Number of Molecules in the Mixture

To calculate the number of molecules in the mixture, we can use the Avogadro's constant, which is approximately 6.022 x 10^23 molecules/mol.

The number of molecules can be calculated using the formula: Number of molecules = Number of moles * Avogadro's constant

Let's calculate the number of molecules for each component of the mixture.

1. Number of Molecules of Nitrogen (N2) - Number of moles of nitrogen (N2) = 0.2 moles - Using Avogadro's constant: Number of molecules of nitrogen (N2) = 0.2 moles * 6.022 x 10^23 molecules/mol

The number of molecules of nitrogen in the mixture is approximately 1.2044 x 10^23 molecules.

2. Number of Molecules of Oxygen (O2) - Number of moles of oxygen (O2) = 1.5 moles - Using Avogadro's constant: Number of molecules of oxygen (O2) = 1.5 moles * 6.022 x 10^23 molecules/mol

The number of molecules of oxygen in the mixture is approximately 9.033 x 10^23 molecules.

3. Number of Molecules of Hydrogen (H2) - Number of moles of hydrogen (H2) = 0.3 moles - Using Avogadro's constant: Number of molecules of hydrogen (H2) = 0.3 moles * 6.022 x 10^23 molecules/mol

The number of molecules of hydrogen in the mixture is approximately 1.8066 x 10^23 molecules.

Calculating the Volume of the Mixture at Standard Conditions

To calculate the volume of the mixture at standard conditions (0°C and 1 atm pressure), we can use the ideal gas law equation: PV = nRT

Where: - P = pressure (in atm) - V = volume (in liters) - n = number of moles - R = ideal gas constant (0.0821 L.atm/mol.K) - T = temperature (in Kelvin)

At standard conditions, the pressure (P) is 1 atm and the temperature (T) is 273.15 K.

Using the ideal gas law, we can calculate the volume of the mixture.

Volume Calculation

- Total number of moles in the mixture = 0.2 moles (N2) + 1.5 moles (O2) + 0.3 moles (H2) = 2 moles - Using the ideal gas law equation: V = (2 moles * 0.0821 L.atm/mol.K * 273.15 K) / 1 atm

The volume of the mixture at standard conditions is approximately 44.43 liters.

Therefore, the mixture contains approximately: - 1.2044 x 10^23 molecules of nitrogen (N2) - 9.033 x 10^23 molecules of oxygen (O2) - 1.8066 x 10^23 molecules of hydrogen (H2) - The mixture occupies approximately 44.43 liters at standard conditions.