Question

Написати рівняння реакцій горіння пропану , бутану ,пентану , гептану .

Answer 1

Объяснение:

Написати рівняння реакцій горіння пропану:

C3H8 + 5O2 → 3CO2↑ + 4H2O

горіння бутану

2C4H10 + 13O2 → 8CO2↑ + 10H2O

горіння пентану

C5H12 + 8O2 → 5CO2↑ + 6H2O

горіння гептану

C7H16 + 11O2 → 7CO2↑ + 8H2O

Answer 2

Equations for the Combustion of Propane, Butane, Pentane, and Heptane

The combustion of hydrocarbons involves the reaction of the hydrocarbon with oxygen to produce carbon dioxide and water. Here are the balanced equations for the combustion of propane, butane, pentane, and heptane:

1. Propane (C3H8): - Equation: C3H8 + 5O2 → 3CO2 + 4H2O - Explanation: One molecule of propane reacts with five molecules of oxygen to produce three molecules of carbon dioxide and four molecules of water.

2. Butane (C4H10): - Equation: 2C4H10 + 13O2 → 8CO2 + 10H2O - Explanation: Two molecules of butane react with thirteen molecules of oxygen to produce eight molecules of carbon dioxide and ten molecules of water.

3. Pentane (C5H12): - Equation: 2C5H12 + 17O2 → 10CO2 + 12H2O - Explanation: Two molecules of pentane react with seventeen molecules of oxygen to produce ten molecules of carbon dioxide and twelve molecules of water.

4. Heptane (C7H16): - Equation: 2C7H16 + 23O2 → 14CO2 + 16H2O - Explanation: Two molecules of heptane react with twenty-three molecules of oxygen to produce fourteen molecules of carbon dioxide and sixteen molecules of water.

Please note that these equations represent the balanced chemical reactions for the complete combustion of propane, butane, pentane, and heptane. In reality, incomplete combustion can occur under certain conditions, leading to the formation of other byproducts such as carbon monoxide (CO) and soot.