Question

Обчисліть масові частки елементів у харчовій соді NaHCO3. СРООЧНОО

Answer 1

Ответ:

Объяснение: Mr(NaHCO3) = 23 + 1 + 12 + 16*3 =84

W(Na) = Ar(Nа) *n / Mr(NaHCO3)  *100% = 23 *1 / 84  *100% = 27%

W(H) = Ar(H) *n / Mr(NaHCO3)  *100% = 1*1 / 84  *100% = 1 %

W(C) = Ar(C) *n / Mr(NaHCO3)  *100% = 12 *1 / 84  *100% = 14%

W(O) = Ar(O) *n / Mr(NaHCO3)  *100% = 16*3 / 84  *100% = 58%

Вроде

Answer 2

I will answer in detail. To calculate the mass fractions of the elements in baking soda NaHCO3, we need to know the relative atomic masses of the elements and the relative molecular mass of the compound. According to the web search results, the relative atomic masses of sodium (Na), hydrogen (H), carbon (C) and oxygen (O) are 23, 1, 12 and 16 respectively . Therefore, the relative molecular mass of NaHCO3 is 23 + 1 + 12 + 3 * 16 = 84. The mass fraction of an element is the ratio of its relative atomic mass multiplied by the number of atoms in the formula to the relative molecular mass of the compound. Thus, the mass fractions of the elements in NaHCO3 are:

- w(Na) = 23 / 84 = 0.2738, or 27.38% - w(H) = 1 / 84 = 0.0119, or 1.19% - w(C) = 12 / 84 = 0.1429, or 14.29% - w(O) = 3 * 16 / 84 = 0.5714, or 57.14%

I hope this helps you with your task.