Question

9 класс 1. В сернокислотный цех производства аккумуляторных батарей поступил 68%-ный раствор серной кислоты объёмом 1000 литров (плотность раствора 1,59 г\мл). Свинцовые аккумуляторные батареи заправляют 39,68%-ным раствором (плотностью 1,3 г\мл). Ввиду производственной необходимости, прибывшую кислоту разбавляют 5%-ным её раствором (плотность 1,032 г\мл). Сколько потребуется 5%-ного и 68%-ного раствора кислоты для приготовления 500 л 39,68%-ного раствора кислоты.

Answer 1

Calculation of the Required Amount of 5% and 68% Sulfuric Acid Solution

To calculate the amount of 5% and 68% sulfuric acid solution needed to prepare a 500 L 39.68% sulfuric acid solution, we need to use the following information:

- The 68% sulfuric acid solution has a volume of 1000 liters and a density of 1.59 g/ml. - The 39.68% sulfuric acid solution has a density of 1.3 g/ml. - The 5% sulfuric acid solution has a density of 1.032 g/ml.

Let's break down the calculation step by step:

1. Calculate the mass of the 39.68% sulfuric acid solution needed: - The density of the 39.68% sulfuric acid solution is 1.3 g/ml. - The volume of the 39.68% sulfuric acid solution needed is 500 L. - Therefore, the mass of the 39.68% sulfuric acid solution needed is: mass = volume x density = 500 L x 1.3 g/ml.

2. Calculate the mass of the 68% sulfuric acid solution needed: - The density of the 68% sulfuric acid solution is 1.59 g/ml. - The volume of the 68% sulfuric acid solution needed can be calculated using the equation: mass = volume x density. - We know that the mass of the 68% sulfuric acid solution is the same as the mass of the 39.68% sulfuric acid solution calculated in step 1. - Therefore, the volume of the 68% sulfuric acid solution needed is: volume = mass / density = (500 L x 1.3 g/ml) / 1.59 g/ml.

3. Calculate the volume of the 5% sulfuric acid solution needed: - The density of the 5% sulfuric acid solution is 1.032 g/ml. - The mass of the 5% sulfuric acid solution needed can be calculated using the equation: mass = volume x density. - We know that the mass of the 5% sulfuric acid solution is 5% of the mass of the 39.68% sulfuric acid solution calculated in step 1. - Therefore, the volume of the 5% sulfuric acid solution needed is: volume = mass / density = (5% x mass of 39.68% sulfuric acid solution) / 1.032 g/ml.

Let's calculate the values:

1. Calculate the mass of the 39.68% sulfuric acid solution needed: - mass = volume x density = 500 L x 1.3 g/ml = 650 g.

2. Calculate the volume of the 68% sulfuric acid solution needed: - volume = mass / density = (650 g) / 1.59 g/ml ≈ 408.18 ml.

3. Calculate the volume of the 5% sulfuric acid solution needed: - volume = (5% x mass of 39.68% sulfuric acid solution) / 1.032 g/ml = (5% x 650 g) / 1.032 g/ml ≈ 31.59 ml.

Therefore, to prepare 500 L of a 39.68% sulfuric acid solution, you will need approximately 408.18 ml of a 68% sulfuric acid solution and approximately 31.59 ml of a 5% sulfuric acid solution.

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