Question

️️️️️️️️️️️️️️️️!!!!!HEEEEEEEEEEEELLLLLLLPPPPPP В порции мела CaCO3 суммарное число атомов всех элементов равно 9,03⋅1023. Вычисли химическое количество мела с точностью до сотых

Answer 1

Відповідь:

Пояснення:

n(CaCO3) = n(Ca) + n(C) +n(3O) =n(CaCO3) / 5

N(CaCO3) =( N (Ca) + N(C) +N(3O))  / 5    = 9,03⋅1023 / 5 = 1,806 *10²³

n(CaCO3) =  N(CaCO3) / Nₐ = 1,806 *10²³ / 6,02*10²³ = 0,3 моль

Answer 2

Calculation of Chemical Quantity of CaCO3

To calculate the chemical quantity of CaCO3 with a given number of atoms, we need to use Avogadro's number and the molar mass of CaCO3.

Avogadro's number (NA) is approximately 6.022 x 10^23, and it represents the number of atoms or molecules in one mole of a substance.

The molar mass of CaCO3 can be calculated by adding up the atomic masses of calcium (Ca), carbon (C), and three oxygen (O) atoms. The atomic masses of these elements are as follows:

- Calcium (Ca): 40.08 g/mol - Carbon (C): 12.01 g/mol - Oxygen (O): 16.00 g/mol

Therefore, the molar mass of CaCO3 is:

Molar mass of CaCO3 = (1 x Ca) + (1 x C) + (3 x O) = (1 x 40.08) + (1 x 12.01) + (3 x 16.00) = 40.08 + 12.01 + 48.00 = 100.09 g/mol

Now, let's calculate the chemical quantity of CaCO3 using the given number of atoms and the molar mass.

Chemical quantity (in moles) = Number of atoms / Avogadro's number = 9.03 x 10^23 / 6.022 x 10^23 ≈ 1.50 moles

To find the chemical quantity with precision to the hundredth place, we can round the result to two decimal places.

Therefore, the chemical quantity of CaCO3 with a sum of 9.03 x 10^23 atoms is approximately 1.50 moles.

Please note that the calculation assumes that all the atoms in the given number are part of CaCO3.