Question

1. Осуществите превращения по схеме: 1) K→K2O→KOH→K2SO4 2) S→SO2→H2SO3→Na2SO3 3) Аl→Al2O3→Al2(SO4)3

Answer 1

@@@@@@@@@@@@@@@@@@@@

Answer 2

1)

4K + O2 = 2K2O

K2O + H2O = 2KOH

2KOH + H2SO4 = K2SO4 + 2H2O

2)

S + O2 = SO2

SO2 + H2O = H2SO3

H2SO3 + 2NaOH = Na2SO3 + 2H2O

3)

4Al + 3O2 = 2Al2O3

Al2O3 + 3H2SO4 = Al2(SO4)3 + 3H2O

Answer 3

Превращения по схеме:

1) K → K2O → KOH → K2SO4 2) S → SO2 → H2SO3 → Na2SO3 3) Аl → Al2O3 → Al2(SO4)3

1) K → K2O → KOH → K2SO4:

- K reacts with oxygen (O) to form potassium oxide (K2O). - Potassium oxide (K2O) reacts with water (H2O) to form potassium hydroxide (KOH). - Potassium hydroxide (KOH) reacts with sulfuric acid (H2SO4) to form potassium sulfate (K2SO4).

2) S → SO2 → H2SO3 → Na2SO3:

- Sulfur (S) reacts with oxygen (O) to form sulfur dioxide (SO2). - Sulfur dioxide (SO2) reacts with water (H2O) to form sulfurous acid (H2SO3). - Sulfurous acid (H2SO3) reacts with sodium hydroxide (NaOH) to form sodium sulfite (Na2SO3).

3) Аl → Al2O3 → Al2(SO4)3:

- Aluminum (Аl) reacts with oxygen (O) to form aluminum oxide (Al2O3). - Aluminum oxide (Al2O3) reacts with sulfuric acid (H2SO4) to form aluminum sulfate (Al2(SO4)3).

Please note that the reactions mentioned above are simplified representations and may involve additional steps or conditions in reality.