Question

1)запишите уравнения возможных реакций между попарно взятыми веществами:SiO2, NaOH, CaO, HNO3, H2O .2) Рассмотрите окислительно- восстановительную реакцию: SiO2+C+N2=CO+Si3N4​

Answer 1

Ответ:

Объяснение:

1) SiO2 + 2NaOH = Na2SiO3 + H2O

SiO2 + CaO= CaSiO3

NaOH + HNO3 =NaNO3 + H2O

CaO + 2HNO3 = Ca(NO3)2 + H2O

CaO + H2O = Ca(OH)2

2) 3SiO2 + 6C + 2N2 = 6CO+ Si3N4

C(0) -2e = C(+2)          6    ок-ие

в-ль

2N2(0)   +12e = 4N(-3)  1    в-ие

ок-ль

Answer 2

#### Possible Reactions: 1) SiO2 + NaOH → Na2SiO3 + H2O 2) CaO + HNO3 → Ca(NO3)2 + H2O 3) HNO3 + H2O → H3O+ + NO3- 4) SiO2 + C + N2 → CO + Si3N4 #### Oxidation-Reduction Reaction: The given reaction, SiO2 + C + N2 → CO + Si3N4, is an example of an oxidation-reduction reaction. In this reaction, silicon dioxide (SiO2) is reduced to silicon nitride (Si3N4), while carbon (C) is oxidized to carbon monoxide (CO). The nitrogen gas (N2) acts as a reactant and does not undergo any oxidation or reduction. #### Explanation: In the given reaction, silicon dioxide (SiO2) reacts with carbon (C) and nitrogen gas (N2) to produce carbon monoxide (CO) and silicon nitride (Si3N4). This reaction involves the transfer of electrons from one reactant to another, resulting in the oxidation of carbon and the reduction of silicon dioxide. The oxidation state of carbon changes from 0 in the elemental form to +2 in carbon monoxide. This indicates that carbon has lost electrons and has been oxidized. On the other hand, the oxidation state of silicon in silicon dioxide changes from +4 to +3 in silicon nitride, indicating that silicon has gained electrons and has been reduced. The balanced equation for the reaction is as follows: SiO2 + 3C + 2N2 → 3CO + Si3N4 Please note that the balanced equation may vary depending on the reaction conditions and stoichiometry. #### Sources: 1) [[SOURCE 1]] 2) [[SOURCE 2]] 3) [[SOURCE 3]]