Question

!!!ДОПОМОЖІТЬ БУДЬ ЛАСКА ІЗ ЗАДАЧАМИ!!! 1)Яка маса солі утвориться, якщо через розчин, що містить 2,5 г натрій гідроксиду, пропустили 11,2 л (н. у.) гідроген сульфіду. 2)Яка маса солі утвориться, якщо розчин, що містить 2,5 г натрій гідроксиду, поглинув 1,68 л (н. у.) карбон(ІV) оксиду. 

Answer 1

Ответ:

1) 2.5/40=0.0625моль naoh

0.0625      x=3.5

naoh+h2s=nahs+h2o

1                 56

2) 2.5/40=0.0625моль naoh

0.0625                 х= 5.25

NaOH + CO2 = NaHCO3

  1                           84

Answer 2

Calculation of Mass of Salt Formed

To calculate the mass of salt formed in both scenarios, we need to determine the balanced chemical equations for the reactions and use stoichiometry to find the mass of the salt.

1) Reaction between Sodium Hydroxide (NaOH) and Hydrogen Sulfide (H2S):

The balanced chemical equation for this reaction is:

2 NaOH + H2S -> Na2S + 2 H2O

According to the equation, 2 moles of NaOH react with 1 mole of H2S to produce 1 mole of Na2S.

Given: - Mass of NaOH = 2.5 g - Volume of H2S = 11.2 L (at standard temperature and pressure)

To find the mass of Na2S formed, we need to follow these steps:

Step 1: Convert the volume of H2S to moles using the ideal gas law. Step 2: Use the mole ratio from the balanced equation to find the moles of Na2S formed. Step 3: Convert the moles of Na2S to grams using the molar mass of Na2S.

Let's calculate the mass of Na2S formed:

Step 1: Convert the volume of H2S to moles. Using the ideal gas law, we can calculate the number of moles of H2S: PV = nRT

Where: P = pressure (at standard temperature and pressure, it is 1 atm) V = volume