Question

H2S+KMnO4=MnO2+S+KOH+H2O

Answer 1

3H2S + 2KMnO4=2MnO2 + 3S + 2KOH + 2H2O

Answer 2

The equation you've written appears to be a chemical reaction, but it's not balanced. To balance it, you need to make sure that there are an equal number of atoms of each element on both sides of the reaction. Let's balance the reaction:

H2S + KMnO4 = MnO2 + S + KOH + H2O

First, let's identify the elements and the number of atoms of each element on both sides of the equation:

On the left side (reactants):

• Hydrogen (H): 2 atoms
• Sulfur (S): 1 atom
• Potassium (K): 1 atom
• Manganese (Mn): 1 atom
• Oxygen (O): 4 atoms

On the right side (products):

• Manganese (Mn): 1 atom
• Oxygen (O): 3 atoms (2 in MnO2 and 1 in KOH)
• Sulfur (S): 1 atom
• Potassium (K): 1 atom
• Hydrogen (H): 2 atoms
• Water (H2O): 1 H and 1 O

Now, we need to balance the equation by adjusting the coefficients (the numbers in front of the chemical formulas) so that the number of atoms is the same on both sides:

H2S + KMnO4 = MnO2 + S + KOH + H2O

Balanced equation:

H2S + 2 KMnO4 = MnO2 + 2 S + 2 KOH + 2 H2O

Now, the equation is balanced. There are an equal number of each type of atom on both sides of the equation, and the law of conservation of mass is satisfied.