Question

NaI+NaNO2+CH3COOH=NO+I2+CH3COONa+H2O

Answer 1

2NaI + 2NaNO2 + 4CH3COOH = 2NO + I2 + 4CH3COONa + 2H2O

Answer 2

The chemical equation you provided is a redox reaction between sodium iodide (NaI), sodium nitrite (NaNO2), and acetic acid (CH3COOH). Here's the balanced equation:

2 NaI + NaNO2 + CH3COOH → NO + I2 + CH3COONa + H2O

In this reaction, sodium iodide (NaI) is oxidized to iodine (I2), and sodium nitrite (NaNO2) is reduced to nitrogen monoxide (NO).

Balanced equation: 2 NaI + NaNO2 + CH3COOH → NO + I2 + CH3COONa + H2O