Question

M(cu(oh)2=4,9г. + hno3. Найти массу соли

Answer 1

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Answer 2

To find the mass of the salt (Cu(NO3)2), we need to first balance the chemical equation and then perform the necessary calculations. The balanced equation for the reaction between Cu(OH)2 and HNO3 is as follows:

Cu(OH)2 + 2HNO3 → Cu(NO3)2 + 2H2O

From the balanced equation, we can see that 1 mole of Cu(OH)2 reacts with 2 moles of HNO3 to produce 1 mole of Cu(NO3)2. Now, we have the molar mass of Cu(OH)2 and HNO3, which are:

Molar mass of Cu(OH)2 (Copper(II) hydroxide) = 97.56 g/mol Molar mass of HNO3 (Nitric acid) = 63.01 g/mol

Next, we have the given mass of Cu(OH)2, which is 4.9 g.

Now, let's proceed with the calculation:

Step 1: Calculate the number of moles of Cu(OH)2: Number of moles = Given mass / Molar mass Number of moles of Cu(OH)2 = 4.9 g / 97.56 g/mol ≈ 0.0502 mol

Step 2: Use the mole ratio to find the number of moles of Cu(NO3)2: From the balanced equation, 1 mole of Cu(OH)2 produces 1 mole of Cu(NO3)2. Number of moles of Cu(NO3)2 = 0.0502 mol

Step 3: Calculate the mass of Cu(NO3)2: Mass of Cu(NO3)2 = Number of moles × Molar mass Mass of Cu(NO3)2 = 0.0502 mol × (63.01 g/mol + 2 * 14.01 g/mol + 6 * 16.00 g/mol) Mass of Cu(NO3)2 ≈ 0.0502 mol × 187.57 g/mol ≈ 9.42 g

The mass of Cu(NO3)2 (the salt) is approximately 9.42 grams.